How to solve 16/21-7/21

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16/21-7/21 | Equatix

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$$16/21-7/21$$

$\frac{3}{7}\approx 0.428571429$

Since $\frac{16}{21}$ and $\frac{7}{21}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-7}{21}$$

Subtract $7$ from $16$ to get $9$.

$$\frac{9}{21}$$

Reduce the fraction $\frac{9}{21}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{7}$$

$\frac{3}{7} = 0.42857142857142855$