How to solve 16/7-1/14

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16/7-1/14 | Equatix

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$$16/7-1/14$$

$\frac{31}{14}\approx 2.214285714$

Least common multiple of $7$ and $14$ is $14$. Convert $\frac{16}{7}$ and $\frac{1}{14}$ to fractions with denominator $14$.

$$\frac{32}{14}-\frac{1}{14}$$

Since $\frac{32}{14}$ and $\frac{1}{14}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-1}{14}$$

Subtract $1$ from $32$ to get $31$.

$$\frac{31}{14}$$

$\frac{31}{2 \cdot 7} = 2\frac{3}{14} = 2.2142857142857144$