Solve 16 * 31 + \{2 * 50 - (5 * 941 / 2 * 20 * 71 * 0 - 1875)\}

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Question

$$16\cdot31+\{2\cdot50-(5\cdot941\div2\cdot20\times71\cdot0-1875)\}$$

Evaluate

$2471$

Solution Steps

Multiply $16$ and $31$ to get $496$.

$$496+2\times 50-\left(\frac{5\times 941}{2}\times 20\times 71\times 0-1875\right)$$

Multiply $2$ and $50$ to get $100$.

$$496+100-\left(\frac{5\times 941}{2}\times 20\times 71\times 0-1875\right)$$

Multiply $5$ and $941$ to get $4705$.

$$496+100-\left(\frac{4705}{2}\times 20\times 71\times 0-1875\right)$$

Express $\frac{4705}{2}\times 20$ as a single fraction.

$$496+100-\left(\frac{4705\times 20}{2}\times 71\times 0-1875\right)$$

Multiply $4705$ and $20$ to get $94100$.

$$496+100-\left(\frac{94100}{2}\times 71\times 0-1875\right)$$

Divide $94100$ by $2$ to get $47050$.

$$496+100-\left(47050\times 71\times 0-1875\right)$$

Multiply $47050$ and $71$ to get $3340550$.

$$496+100-\left(3340550\times 0-1875\right)$$

Multiply $3340550$ and $0$ to get $0$.

$$496+100-\left(0-1875\right)$$

Subtract $1875$ from $0$ to get $-1875$.

$$496+100-\left(-1875\right)$$

The opposite of $-1875$ is $1875$.

$$496+100+1875$$

Add $100$ and $1875$ to get $1975$.

$$496+1975$$

Add $496$ and $1975$ to get $2471$.

$$2471$$

Show Solution

Factor

$7\times 353$