Solve 16-[14-(-2)]-(-6)^ 2 ] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$16-[14-(-2)]-(-6)^{2}]$$

Evaluate

$-36$

Solution Steps

The opposite of $-2$ is $2$.

$$16-\left(14+2\right)-\left(-6\right)^{2}$$

Add $14$ and $2$ to get $16$.

$$16-16-\left(-6\right)^{2}$$

Subtract $16$ from $16$ to get $0$.

$$0-\left(-6\right)^{2}$$

Calculate $-6$ to the power of $2$ and get $36$.

$$0-36$$

Subtract $36$ from $0$ to get $-36$.

$$-36$$

Factor

$-36$