How to solve 16-3/5x=x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16-3/5x=x | Equatix

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$$16-3/5x=x$$

$x=10$

Subtract $x$ from both sides.

$$16-\frac{3}{5}x-x=0$$

Combine $-\frac{3}{5}x$ and $-x$ to get $-\frac{8}{5}x$.

$$16-\frac{8}{5}x=0$$

Subtract $16$ from both sides. Anything subtracted from zero gives its negation.

$$-\frac{8}{5}x=-16$$

Multiply both sides by $-\frac{5}{8}$, the reciprocal of $-\frac{8}{5}$.

$$x=-16\left(-\frac{5}{8}\right)$$

Express $-16\left(-\frac{5}{8}\right)$ as a single fraction.

$$x=\frac{-16\left(-5\right)}{8}$$

Multiply $-16$ and $-5$ to get $80$.

$$x=\frac{80}{8}$$

Divide $80$ by $8$ to get $10$.

$$x=10$$