$$16(a-b)^{2}-(4a-+b)=$$
$16\left(a-b\right)^{2}+b-4a$
$$16\left(a^{2}-2ab+b^{2}\right)-\left(4a-b\right)$$
$$16a^{2}-32ab+16b^{2}-\left(4a-b\right)$$
$$16a^{2}-32ab+16b^{2}-4a+b$$
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$16a^{2}-32ab-4a+16b^{2}+b$
