$$16 + ( - 21 ) \div 7 \times \{ 9 + [ 56 \div ( - 8 ) ] \}$$
$10$
$$16-3\left(9+\frac{56}{-8}\right)$$
$$16-3\left(9-7\right)$$
$$16-3\times 2$$
$$16-6$$
$$10$$
Show Solution
Hide Solution
$2\times 5$