Question

$$16^{\frac{1}{5}}\cdot16^{\frac{1}{5}}; 16\frac{-3}{5}$$

Answer

$$2^(4/5)*2^(4/5);16*-3/5$$

Solution


Rewrite \(16\) as \({2}^{4}\).
\[\begin{aligned}&\sqrt[5]{{2}^{4}}\sqrt[5]{{2}^{4}}\\&16\times \frac{-3}{5}\end{aligned}\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[\begin{aligned}&{2}^{\frac{4}{5}}\times {2}^{\frac{4}{5}}\\&16\times \frac{-3}{5}\end{aligned}\]