How to solve 6 * 10 ^ - 19 * C

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 * 10 ^ - 19 * C | Equatix

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$$1.6\times10^{-19}C.$$

$\frac{C}{6250000000000000000}$

$0.00000000000000000016$

Calculate $10$ to the power of $-19$ and get $\frac{1}{10000000000000000000}$.

$$\frac{\mathrm{d}}{\mathrm{d}C}(1.6\times \frac{1}{10000000000000000000}C)$$

Multiply $1.6$ and $\frac{1}{10000000000000000000}$ to get $\frac{1}{6250000000000000000}$.

$$\frac{\mathrm{d}}{\mathrm{d}C}(\frac{1}{6250000000000000000}C)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$\frac{1}{6250000000000000000}C^{1-1}$$

Subtract $1$ from $1$.

$$\frac{1}{6250000000000000000}C^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$\frac{1}{6250000000000000000}\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$\frac{1}{6250000000000000000}$$