How to solve 16|.7/2.1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16|.7/2.1 | Equatix

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$$16|.7\div2.1$$

$\frac{16}{3}\approx 5.333333333$

Expand $\frac{0.7}{2.1}$ by multiplying both numerator and the denominator by $10$.

$$16|\frac{7}{21}|$$

Reduce the fraction $\frac{7}{21}$ to lowest terms by extracting and canceling out $7$.

$$16|\frac{1}{3}|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $\frac{1}{3}$ is $\frac{1}{3}$.

$$16\times \frac{1}{3}$$

Multiply $16$ and $\frac{1}{3}$ to get $\frac{16}{3}$.

$$\frac{16}{3}$$

$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$