How to solve 16a-3=-5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16a-3=-5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$16a-3=-5$$

Solve for a

$a=-\frac{1}{8}=-0.125$

Steps for Solving Linear Equation

Add $3$ to both sides.

$$16a=-5+3$$

Add $-5$ and $3$ to get $-2$.

$$16a=-2$$

Divide both sides by $16$.

$$a=\frac{-2}{16}$$

Reduce the fraction $\frac{-2}{16}$ to lowest terms by extracting and canceling out $2$.

$$a=-\frac{1}{8}$$

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Question

Solve for a

Steps for Solving Linear Equation