How to solve 16a ^ 2 + 9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 16a ^ 2 + 9 | Equatix

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Question

$$16a^{2}+9$$

Differentiate w.r.t. a

$32a$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$2\times 16a^{2-1}$$

Multiply $2$ times $16$.

$$32a^{2-1}$$

Subtract $1$ from $2$.

$$32a^{1}$$

For any term $t$, $t^{1}=t$.

$$32a$$

Show Solution

Evaluate

$16a^{2}+9$