$$16x2-24x+8=0$$
$x=\frac{2x_{2}+1}{3}$
$$-24x+8=-16x_{2}$$
$$-24x=-16x_{2}-8$$
$$\frac{-24x}{-24}=\frac{-16x_{2}-8}{-24}$$
$$x=\frac{-16x_{2}-8}{-24}$$
$$x=\frac{2x_{2}+1}{3}$$
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$x_{2}=\frac{3x-1}{2}$
$$16x_{2}+8=24x$$
$$16x_{2}=24x-8$$
$$\frac{16x_{2}}{16}=\frac{24x-8}{16}$$
$$x_{2}=\frac{24x-8}{16}$$
$$x_{2}=\frac{3x-1}{2}$$
