Solve 17 + 6p = 9 12 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$17 + 6 p = 9$$

Solve for p

$p = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$

Steps for Solving Linear Equation

Subtract $17$ from both sides.

$$6p=9-17$$

Subtract $17$ from $9$ to get $-8$.

$$6p=-8$$

Divide both sides by $6$.

$$p=\frac{-8}{6}$$

Reduce the fraction $\frac{-8}{6}$ to lowest terms by extracting and canceling out $2$.

$$p=-\frac{4}{3}$$