How to solve 1709 imes293=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1709\times293= | Equatix

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Question

$$1709 \times 293=$$

Evaluate

$500737$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}1709\\\underline{\times\phantom{999}293}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 1709 with 3. Write the result 5127 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}1709\\\underline{\times\phantom{999}293}\\\phantom{\times99}5127\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 1709 with 9. Write the result 15381 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}1709\\\underline{\times\phantom{999}293}\\\phantom{\times99}5127\\\phantom{\times}15381\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 1709 with 2. Write the result 3418 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}1709\\\underline{\times\phantom{999}293}\\\phantom{\times99}5127\\\phantom{\times}15381\phantom{9}\\\underline{\phantom{\times}3418\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}1709\\\underline{\times\phantom{999}293}\\\phantom{\times99}5127\\\phantom{\times}15381\phantom{9}\\\underline{\phantom{\times}3418\phantom{99}}\\\phantom{\times}500737\end{array}$$

Show Solution

Factor

$293\times 1709$