$$18 { a }^{ 5 } -6 { a }^{ 4 } b+9 { a }^{ 3 } { b }^{ 2 } =$$
$3\left(6a^{2}-2ab+3b^{2}\right)a^{3}$
$$3\left(6a^{5}-2a^{4}b+3a^{3}b^{2}\right)$$
$$a^{3}\left(6a^{2}-2ab+3b^{2}\right)$$
$$3a^{3}\left(6a^{2}-2ab+3b^{2}\right)$$
Show Solution
Hide Solution