How to solve 18/14+1/6=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 18/14+1/6= | Equatix

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$$18/14+1/6=$$

$\frac{61}{42}\approx 1.452380952$

Reduce the fraction $\frac{18}{14}$ to lowest terms by extracting and canceling out $2$.

$$\frac{9}{7}+\frac{1}{6}$$

Least common multiple of $7$ and $6$ is $42$. Convert $\frac{9}{7}$ and $\frac{1}{6}$ to fractions with denominator $42$.

$$\frac{54}{42}+\frac{7}{42}$$

Since $\frac{54}{42}$ and $\frac{7}{42}$ have the same denominator, add them by adding their numerators.

$$\frac{54+7}{42}$$

Add $54$ and $7$ to get $61$.

$$\frac{61}{42}$$

$\frac{61}{2 \cdot 3 \cdot 7} = 1\frac{19}{42} = 1.4523809523809523$