How to solve 18-[2+(7-3-8)-10]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 18-[2+(7-3-8)-10] | Equatix

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3(r+2s)=2t-4

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Question

$$18-[2+(7-3-8)-10]$$

Evaluate

$30$

Solution Steps

Add $2$ and $7$ to get $9$.

$$18-\left(9-3-8-10\right)$$

Subtract $3$ from $9$ to get $6$.

$$18-\left(6-8-10\right)$$

Subtract $8$ from $6$ to get $-2$.

$$18-\left(-2-10\right)$$

Subtract $10$ from $-2$ to get $-12$.

$$18-\left(-12\right)$$

The opposite of $-12$ is $12$.

$$18+12$$

Add $18$ and $12$ to get $30$.

$$30$$

Show Solution

Factor

$2\times 3\times 5$

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