$$18(-7+16)-4(91-160)+5(-26+20)$$
$408$
$$18\times 9-4\left(91-160\right)+5\left(-26+20\right)$$
$$162-4\left(91-160\right)+5\left(-26+20\right)$$
$$162-4\left(-69\right)+5\left(-26+20\right)$$
$$162-\left(-276\right)+5\left(-26+20\right)$$
$$162+276+5\left(-26+20\right)$$
$$438+5\left(-26+20\right)$$
$$438+5\left(-6\right)$$
$$438-30$$
$$408$$
Show Solution
Hide Solution
$2^{3}\times 3\times 17$