How to solve 1.8+0.7/-35/43

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1.8+0.7/-35/43 | Equatix

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Question

$$1.8+0.7/-35/43$$

Evaluate

$\frac{3869}{2150}\approx 1.799534884$

Solution Steps

Express $\frac{\frac{0.7}{-35}}{43}$ as a single fraction.

$$1.8+\frac{0.7}{-35\times 43}$$

Multiply $-35$ and $43$ to get $-1505$.

$$1.8+\frac{0.7}{-1505}$$

Expand $\frac{0.7}{-1505}$ by multiplying both numerator and the denominator by $10$.

$$1.8+\frac{7}{-15050}$$

Reduce the fraction $\frac{7}{-15050}$ to lowest terms by extracting and canceling out $7$.

$$1.8-\frac{1}{2150}$$

Convert decimal number $1.8$ to fraction $\frac{18}{10}$. Reduce the fraction $\frac{18}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{9}{5}-\frac{1}{2150}$$

Least common multiple of $5$ and $2150$ is $2150$. Convert $\frac{9}{5}$ and $\frac{1}{2150}$ to fractions with denominator $2150$.

$$\frac{3870}{2150}-\frac{1}{2150}$$

Since $\frac{3870}{2150}$ and $\frac{1}{2150}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3870-1}{2150}$$

Subtract $1$ from $3870$ to get $3869$.

$$\frac{3869}{2150}$$

Show Solution

Factor

$\frac{53 \cdot 73}{2 \cdot 43 \cdot 5 ^ {2}} = 1\frac{1719}{2150} = 1.7995348837209302$