Solve Verify the following a)18*[7+(-3)]=[18*7]+[18*(-3] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$18 \times [ 7 + ( - 3 ) ] = [ 18 \times 7 ] + [ 18 \times ( - 3 ) ]$$

Verify

$\text{true}$

Solution Steps

Subtract $3$ from $7$ to get $4$.

$$18\times 4=18\times 7+18\left(-3\right)$$

Multiply $18$ and $4$ to get $72$.

$$72=18\times 7+18\left(-3\right)$$

Multiply $18$ and $7$ to get $126$. Multiply $18$ and $-3$ to get $-54$.

$$72=126-54$$

Subtract $54$ from $126$ to get $72$.

$$72=72$$

Compare $72$ and $72$.

$$\text{true}$$