Solve 18\times[7+(-3)]=[18\times7]+[18\times(-3) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$18 \times [7+(-3)]=[18 \times 7]+[18 \times (-3)$$

Answer

[No Solution]

Solution

Remove parentheses.

Simplify negative sign.

No Solution