$$180 \div \{ (72 \div 8)-(-5+2 \times 4+(-3)) \}$$
$20$
$$\frac{180}{9-\left(-5+2\times 4-3\right)}$$
$$\frac{180}{9-\left(-5+8-3\right)}$$
$$\frac{180}{9-\left(3-3\right)}$$
$$\frac{180}{9-0}$$
$$\frac{180}{9}$$
$$20$$
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$2^{2}\times 5$
