$$1800\div[10\{(12-6)+(24-12)\}]$$
$10$
$$\frac{1800}{10\left(6+24-12\right)}$$
$$\frac{1800}{10\left(30-12\right)}$$
$$\frac{1800}{10\times 18}$$
$$\frac{1800}{180}$$
$$10$$
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$2\times 5$
