How to solve 18x - 71 > 1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 18x - 71 > 1 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$18x-71>1$$

Solve for x

$x>4$

Solution Steps

Add $71$ to both sides.

$$18x>1+71$$

Add $1$ and $71$ to get $72$.

$$18x>72$$

Divide both sides by $18$. Since $18$ is positive, the inequality direction remains the same.

$$x>\frac{72}{18}$$

Divide $72$ by $18$ to get $4$.

$$x>4$$

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Solve for x

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