How to solve 18x+9x-20=28x+80

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 18x+9x-20=28x+80 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$18x+9x-20=28x+80$$

Solve for x

$x=-100$

Steps for Solving Linear Equation

Combine $18x$ and $9x$ to get $27x$.

$$27x-20=28x+80$$

Subtract $28x$ from both sides.

$$27x-20-28x=80$$

Combine $27x$ and $-28x$ to get $-x$.

$$-x-20=80$$

Add $20$ to both sides.

$$-x=80+20$$

Add $80$ and $20$ to get $100$.

$$-x=100$$

Multiply both sides by $-1$.

$$x=-100$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps for Solving Linear Equation