How to solve 19/8+1/6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 19/8+1/6 | Equatix

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$$19/8+1/6$$

$\frac{61}{24}\approx 2.541666667$

Least common multiple of $8$ and $6$ is $24$. Convert $\frac{19}{8}$ and $\frac{1}{6}$ to fractions with denominator $24$.

$$\frac{57}{24}+\frac{4}{24}$$

Since $\frac{57}{24}$ and $\frac{4}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{57+4}{24}$$

Add $57$ and $4$ to get $61$.

$$\frac{61}{24}$$

$\frac{61}{2 ^ {3} \cdot 3} = 2\frac{13}{24} = 2.5416666666666665$