How to solve 1988 imes12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1988\times12 | Equatix

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Question

$$1988 \times 12$$

Evaluate

$23856$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9}1988\\\underline{\times\phantom{999}12}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 1988 with 2. Write the result 3976 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}1988\\\underline{\times\phantom{999}12}\\\phantom{\times9}3976\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 1988 with 1. Write the result 1988 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9}1988\\\underline{\times\phantom{999}12}\\\phantom{\times9}3976\\\underline{\phantom{\times}1988\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times9}1988\\\underline{\times\phantom{999}12}\\\phantom{\times9}3976\\\underline{\phantom{\times}1988\phantom{9}}\\\phantom{\times}23856\end{array}$$

Show Solution

Factor

$2^{4}\times 3\times 7\times 71$