$$1Af3\cdot9-1\cdot2\times3\cdot8\div2\cdot4+1\cdot46$$
$9Af_{3}-50$
$$9Af_{3}-\frac{1\times 2\times 3\times 8}{2}\times 4+1\times 46$$
$$9Af_{3}-3\times 8\times 4+1\times 46$$
$$9Af_{3}-24\times 4+1\times 46$$
$$9Af_{3}-96+1\times 46$$
$$9Af_{3}-96+46$$
$$9Af_{3}-50$$
Show Solution
Hide Solution
$9f_{3}$
