$\left\{\begin{matrix}y=-\frac{3-5z}{x^{4}}\text{, }&x\neq 0\\y\in \mathrm{C}\text{, }&z=\frac{3}{5}\text{ and }x=0\end{matrix}\right.$

$\left\{\begin{matrix}y=-\frac{3-5z}{x^{4}}\text{, }&x\neq 0\\y\in \mathrm{R}\text{, }&z=\frac{3}{5}\text{ and }x=0\end{matrix}\right.$

$\left\{\begin{matrix}x=\sqrt{2}\left(-\frac{1}{2}+\frac{1}{2}i\right)y^{-\frac{1}{4}}\sqrt[4]{3-5z}\text{; }x=\sqrt{2}\left(\frac{1}{2}+\frac{1}{2}i\right)y^{-\frac{1}{4}}\sqrt[4]{3-5z}\text{; }x=\sqrt{2}\left(-\frac{1}{2}-\frac{1}{2}i\right)y^{-\frac{1}{4}}\sqrt[4]{3-5z}\text{; }x=\sqrt{2}\left(\frac{1}{2}-\frac{1}{2}i\right)y^{-\frac{1}{4}}\sqrt[4]{3-5z}\text{, }&y\neq 0\\x\in \mathrm{C}\text{, }&z=\frac{3}{5}\text{ and }y=0\end{matrix}\right.$

$\left\{\begin{matrix}x=\sqrt[4]{\frac{5z-3}{y}}\text{; }x=-\sqrt[4]{\frac{5z-3}{y}}\text{, }&\left(z\leq \frac{3}{5}\text{ and }y<0\right)\text{ or }\left(z\geq \frac{3}{5}\text{ and }y>0\right)\\x\in \mathrm{R}\text{, }&z=\frac{3}{5}\text{ and }y=0\end{matrix}\right.$