Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$2\ \cos^{2}+3+g^{2}=8$$

Answer

$$g=sqrt(2*(4-cos^23)),-sqrt(2*(4-cos^23))$$

Solution


Subtract \(2{cos}^{23}\) from both sides.
\[{g}^{2}=8-2{cos}^{23}\]
Take the square root of both sides.
\[g=\pm \sqrt{8-2{cos}^{23}}\]
Factor out the common term \(2\).
\[g=\pm \sqrt{2(4-{cos}^{23})}\]

Decimal Form: ±2.828427

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