Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$2 { \times }^{ { 2 }^{ } } +3 \times -2=0$$

Answer

[No Solution]

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2{}^{1+{2}^{}}+3\times -2=0\]
Simplify  \(3\times -2\)  to  \(-6\).
\[2{}^{1+{2}^{}}-6=0\]
Since \(2{}^{1+{2}^{}}-6=0\) is false, there is no solution.
No Solution
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