Quadratic polynomial can be factored using the transformation $ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$, where $x_{1}$ and $x_{2}$ are the solutions of the quadratic equation $ax^{2}+bx+c=0$.
$$2x^{2}-7x+1=0$$
All equations of the form $ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$. The quadratic formula gives two solutions, one when $±$ is addition and one when it is subtraction.
Now solve the equation $x=\frac{7±\sqrt{41}}{4}$ when $±$ is plus. Add $7$ to $\sqrt{41}$.
$$x=\frac{\sqrt{41}+7}{4}$$
Now solve the equation $x=\frac{7±\sqrt{41}}{4}$ when $±$ is minus. Subtract $\sqrt{41}$ from $7$.
$$x=\frac{7-\sqrt{41}}{4}$$
Factor the original expression using $ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$. Substitute $\frac{7+\sqrt{41}}{4}$ for $x_{1}$ and $\frac{7-\sqrt{41}}{4}$ for $x_{2}$.
