Question

$$2 { x }^{ 2 } -x-3=0$$

Answer

x=-1,3/2

Solution


Split the second term in \(2{x}^{2}-x-3\) into two terms.
\[2{x}^{2}+2x-3x-3=0\]
Factor out common terms in the first two terms, then in the last two terms.
\[2x(x+1)-3(x+1)=0\]
Factor out the common term \(x+1\).
\[(x+1)(2x-3)=0\]
Solve for \(x\).
\[x=-1,\frac{3}{2}\]

Decimal Form: -1, 1.5