Question

$$2 { x }^{ 2 } +x- \frac{ 1 }{ 8 } factorize$$

Answer

$$2*x^2+x-(f*a*c*t*o*r*IM*z*e)/8$$

Solution


Simplify  \(\frac{1}{8}factor\imath ze\)  to  \(\frac{factor\imath ze}{8}\).
\[2{x}^{2}+x-\frac{factor\imath ze}{8}\]