How to solve 2/10 * 10 ^ - 1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/10 * 10 ^ - 1 | Equatix

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$$2\div10\times10^{-1}$$

$\frac{1}{50}=0.02$

Reduce the fraction $\frac{2}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{5}\times 10^{-1}$$

Calculate $10$ to the power of $-1$ and get $\frac{1}{10}$.

$$\frac{1}{5}\times \frac{1}{10}$$

Multiply $\frac{1}{5}$ and $\frac{1}{10}$ to get $\frac{1}{50}$.

$$\frac{1}{50}$$

$\frac{1}{2 \cdot 5 ^ {2}} = 0.02$