How to solve 2/3+4/5-7/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/3+4/5-7/5 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$2/3+4/5-7/5$$

$\frac{1}{15}\approx 0.066666667$

Least common multiple of $3$ and $5$ is $15$. Convert $\frac{2}{3}$ and $\frac{4}{5}$ to fractions with denominator $15$.

$$\frac{10}{15}+\frac{12}{15}-\frac{7}{5}$$

Since $\frac{10}{15}$ and $\frac{12}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{10+12}{15}-\frac{7}{5}$$

Add $10$ and $12$ to get $22$.

$$\frac{22}{15}-\frac{7}{5}$$

Least common multiple of $15$ and $5$ is $15$. Convert $\frac{22}{15}$ and $\frac{7}{5}$ to fractions with denominator $15$.

$$\frac{22}{15}-\frac{21}{15}$$

Since $\frac{22}{15}$ and $\frac{21}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{22-21}{15}$$

Subtract $21$ from $22$ to get $1$.

$$\frac{1}{15}$$

$\frac{1}{3 \cdot 5} = 0.06666666666666667$