How to solve 2/3X+1/2=10/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/3X+1/2=10/5 | Equatix

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$$2/3X+1/2=10/5$$

$X = \frac{9}{4} = 2\frac{1}{4} = 2.25$

Divide $10$ by $5$ to get $2$.

$$\frac{2}{3}X+\frac{1}{2}=2$$

Subtract $\frac{1}{2}$ from both sides.

$$\frac{2}{3}X=2-\frac{1}{2}$$

Convert $2$ to fraction $\frac{4}{2}$.

$$\frac{2}{3}X=\frac{4}{2}-\frac{1}{2}$$

Since $\frac{4}{2}$ and $\frac{1}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{3}X=\frac{4-1}{2}$$

Subtract $1$ from $4$ to get $3$.

$$\frac{2}{3}X=\frac{3}{2}$$

Multiply both sides by $\frac{3}{2}$, the reciprocal of $\frac{2}{3}$.

$$X=\frac{3}{2}\times \frac{3}{2}$$

Multiply $\frac{3}{2}$ times $\frac{3}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$X=\frac{3\times 3}{2\times 2}$$

Do the multiplications in the fraction $\frac{3\times 3}{2\times 2}$.

$$X=\frac{9}{4}$$