How to solve 2/3x+1/5=10/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/3x+1/5=10/5 | Equatix

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$$2/3x+1/5=10/5$$

$x = \frac{27}{10} = 2\frac{7}{10} = 2.7$

Divide $10$ by $5$ to get $2$.

$$\frac{2}{3}x+\frac{1}{5}=2$$

Subtract $\frac{1}{5}$ from both sides.

$$\frac{2}{3}x=2-\frac{1}{5}$$

Convert $2$ to fraction $\frac{10}{5}$.

$$\frac{2}{3}x=\frac{10}{5}-\frac{1}{5}$$

Since $\frac{10}{5}$ and $\frac{1}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{3}x=\frac{10-1}{5}$$

Subtract $1$ from $10$ to get $9$.

$$\frac{2}{3}x=\frac{9}{5}$$

Multiply both sides by $\frac{3}{2}$, the reciprocal of $\frac{2}{3}$.

$$x=\frac{9}{5}\times \frac{3}{2}$$

Multiply $\frac{9}{5}$ times $\frac{3}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{9\times 3}{5\times 2}$$

Do the multiplications in the fraction $\frac{9\times 3}{5\times 2}$.

$$x=\frac{27}{10}$$