1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/7+3/8 | Equatix

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Question

$$2/7+3/8$$

$\frac{37}{56}\approx 0.660714286$

Least common multiple of $7$ and $8$ is $56$. Convert $\frac{2}{7}$ and $\frac{3}{8}$ to fractions with denominator $56$.

$$\frac{16}{56}+\frac{21}{56}$$

Since $\frac{16}{56}$ and $\frac{21}{56}$ have the same denominator, add them by adding their numerators.

$$\frac{16+21}{56}$$

Add $16$ and $21$ to get $37$.

$$\frac{37}{56}$$

$\frac{37}{2 ^ {3} \cdot 7} = 0.6607142857142857$