How to solve 2(1)/(3)+1(2)/(4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(1)/(3)+1(2)/(4) | Equatix

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Question

$$2 \frac{ 1 }{ 3 } +1 \frac{ 2 }{ 4 }$$

Evaluate

$\frac{23}{6}\approx 3.833333333$

Solution Steps

Multiply $2$ and $3$ to get $6$.

$$\frac{6+1}{3}+\frac{1\times 4+2}{4}$$

Add $6$ and $1$ to get $7$.

$$\frac{7}{3}+\frac{1\times 4+2}{4}$$

Multiply $1$ and $4$ to get $4$.

$$\frac{7}{3}+\frac{4+2}{4}$$

Add $4$ and $2$ to get $6$.

$$\frac{7}{3}+\frac{6}{4}$$

Reduce the fraction $\frac{6}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{3}+\frac{3}{2}$$

Least common multiple of $3$ and $2$ is $6$. Convert $\frac{7}{3}$ and $\frac{3}{2}$ to fractions with denominator $6$.

$$\frac{14}{6}+\frac{9}{6}$$

Since $\frac{14}{6}$ and $\frac{9}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{14+9}{6}$$

Add $14$ and $9$ to get $23$.

$$\frac{23}{6}$$

Show Solution

Factor

$\frac{23}{2 \cdot 3} = 3\frac{5}{6} = 3.8333333333333335$