$$2 \frac { 1 } { 3 } \times ( \frac { 2 } { 3 } + \frac { 5 } { 6 } ) = ( \frac { 1 } { 3 } \times \frac { 2 } { 3 } ) + ( \frac { 1 } { 3 } \times \frac { 5 } { 6 } )$$
$\text{false}$
$$2\left(2\times 3+1\right)\left(\frac{2}{3}+\frac{5}{6}\right)=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$2\left(6+1\right)\left(\frac{2}{3}+\frac{5}{6}\right)=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$2\times 7\left(\frac{2}{3}+\frac{5}{6}\right)=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$14\left(\frac{2}{3}+\frac{5}{6}\right)=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$14\left(\frac{4}{6}+\frac{5}{6}\right)=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$14\times \frac{4+5}{6}=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$14\times \frac{9}{6}=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$14\times \frac{3}{2}=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$\frac{14\times 3}{2}=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$\frac{42}{2}=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$21=2\times \frac{2}{3}+2\times \frac{5}{6}$$
$$21=\frac{2\times 2}{3}+2\times \frac{5}{6}$$
$$21=\frac{4}{3}+2\times \frac{5}{6}$$
$$21=\frac{4}{3}+\frac{2\times 5}{6}$$
$$21=\frac{4}{3}+\frac{10}{6}$$
$$21=\frac{4}{3}+\frac{5}{3}$$
$$21=\frac{4+5}{3}$$
$$21=\frac{9}{3}$$
$$21=3$$
$$\text{false}$$
Show Solution
Hide Solution
