1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 3 ५ | Equatix

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Question

$$2 \frac { 1 } { 8 } + 1 \frac { 1 } { 3 } + 3 \frac { 3 } { 4 }$$

Evaluate

$\frac{173}{24}\approx 7.208333333$

Solution Steps

Multiply $2$ and $8$ to get $16$.

$$\frac{16+1}{8}+\frac{1\times 3+1}{3}+\frac{3\times 4+3}{4}$$

Add $16$ and $1$ to get $17$.

$$\frac{17}{8}+\frac{1\times 3+1}{3}+\frac{3\times 4+3}{4}$$

Multiply $1$ and $3$ to get $3$.

$$\frac{17}{8}+\frac{3+1}{3}+\frac{3\times 4+3}{4}$$

Add $3$ and $1$ to get $4$.

$$\frac{17}{8}+\frac{4}{3}+\frac{3\times 4+3}{4}$$

Least common multiple of $8$ and $3$ is $24$. Convert $\frac{17}{8}$ and $\frac{4}{3}$ to fractions with denominator $24$.

$$\frac{51}{24}+\frac{32}{24}+\frac{3\times 4+3}{4}$$

Since $\frac{51}{24}$ and $\frac{32}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{51+32}{24}+\frac{3\times 4+3}{4}$$

Add $51$ and $32$ to get $83$.

$$\frac{83}{24}+\frac{3\times 4+3}{4}$$

Multiply $3$ and $4$ to get $12$.

$$\frac{83}{24}+\frac{12+3}{4}$$

Add $12$ and $3$ to get $15$.

$$\frac{83}{24}+\frac{15}{4}$$

Least common multiple of $24$ and $4$ is $24$. Convert $\frac{83}{24}$ and $\frac{15}{4}$ to fractions with denominator $24$.

$$\frac{83}{24}+\frac{90}{24}$$

Since $\frac{83}{24}$ and $\frac{90}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{83+90}{24}$$

Add $83$ and $90$ to get $173$.

$$\frac{173}{24}$$

Show Solution

Factor

$\frac{173}{2 ^ {3} \cdot 3} = 7\frac{5}{24} = 7.208333333333333$