How to solve 2 1/9; 1 1/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 1/9; 1 1/3 | Equatix

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$$2\frac{1}{9}; 1\frac{1}{3}$$

$-\frac{76}{27}\approx -2.814814815$

Multiply $2$ and $9$ to get $18$.

$$\left(-\frac{18+1}{9}\right)\times \frac{1\times 3+1}{3}$$

Add $18$ and $1$ to get $19$.

$$-\frac{19}{9}\times \frac{3+1}{3}$$

Add $3$ and $1$ to get $4$.

$$-\frac{19}{9}\times \frac{4}{3}$$

Multiply $-\frac{19}{9}$ times $\frac{4}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{-19\times 4}{9\times 3}$$

Do the multiplications in the fraction $\frac{-19\times 4}{9\times 3}$.

$$\frac{-76}{27}$$

Fraction $\frac{-76}{27}$ can be rewritten as $-\frac{76}{27}$ by extracting the negative sign.

$$-\frac{76}{27}$$

$-\frac{76}{27} = -2\frac{22}{27} = -2.814814814814815$