Solve 2 10/2 * 8/4 * (2/6 - 1/2) * q | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2\frac{10}{2}\times\frac{8}{4}(\frac{2}{6}-\frac{1}{2})q$$

Evaluate

$-\frac{7q}{3}$

Solution Steps

Multiply $2$ and $2$ to get $4$.

$$\frac{4+10}{2}\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Add $4$ and $10$ to get $14$.

$$\frac{14}{2}\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Divide $14$ by $2$ to get $7$.

$$7\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Divide $8$ by $4$ to get $2$.

$$7\times 2\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Multiply $7$ and $2$ to get $14$.

$$14\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Reduce the fraction $\frac{2}{6}$ to lowest terms by extracting and canceling out $2$.

$$14\left(\frac{1}{3}-\frac{1}{2}\right)q$$

Least common multiple of $3$ and $2$ is $6$. Convert $\frac{1}{3}$ and $\frac{1}{2}$ to fractions with denominator $6$.

$$14\left(\frac{2}{6}-\frac{3}{6}\right)q$$

Since $\frac{2}{6}$ and $\frac{3}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$14\times \frac{2-3}{6}q$$

Subtract $3$ from $2$ to get $-1$.

$$14\left(-\frac{1}{6}\right)q$$

Express $14\left(-\frac{1}{6}\right)$ as a single fraction.

$$\frac{14\left(-1\right)}{6}q$$

Multiply $14$ and $-1$ to get $-14$.

$$\frac{-14}{6}q$$

Reduce the fraction $\frac{-14}{6}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{7}{3}q$$

Expand

$-\frac{7q}{3}$

Solution Steps

Multiply $2$ and $2$ to get $4$.

$$\frac{4+10}{2}\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Add $4$ and $10$ to get $14$.

$$\frac{14}{2}\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Divide $14$ by $2$ to get $7$.

$$7\times \frac{8}{4}\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Divide $8$ by $4$ to get $2$.

$$7\times 2\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Multiply $7$ and $2$ to get $14$.

$$14\left(\frac{2}{6}-\frac{1}{2}\right)q$$

Reduce the fraction $\frac{2}{6}$ to lowest terms by extracting and canceling out $2$.

$$14\left(\frac{1}{3}-\frac{1}{2}\right)q$$

Least common multiple of $3$ and $2$ is $6$. Convert $\frac{1}{3}$ and $\frac{1}{2}$ to fractions with denominator $6$.

$$14\left(\frac{2}{6}-\frac{3}{6}\right)q$$

Since $\frac{2}{6}$ and $\frac{3}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$14\times \frac{2-3}{6}q$$

Subtract $3$ from $2$ to get $-1$.

$$14\left(-\frac{1}{6}\right)q$$

Express $14\left(-\frac{1}{6}\right)$ as a single fraction.

$$\frac{14\left(-1\right)}{6}q$$

Multiply $14$ and $-1$ to get $-14$.

$$\frac{-14}{6}q$$

Reduce the fraction $\frac{-14}{6}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{7}{3}q$$