Factor $96=4^{2}\times 6$. Rewrite the square root of the product $\sqrt{4^{2}\times 6}$ as the product of square roots $\sqrt{4^{2}}\sqrt{6}$. Take the square root of $4^{2}$.
$$2\times \frac{1}{2\times 4\sqrt{6}}$$
Multiply $2$ and $4$ to get $8$.
$$2\times \frac{1}{8\sqrt{6}}$$
Rationalize the denominator of $\frac{1}{8\sqrt{6}}$ by multiplying numerator and denominator by $\sqrt{6}$.
