How to solve 2 2/3 * 7/10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 2/3 * 7/10 | Equatix

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$$2\frac{2}{3}\times\frac{7}{10}$$

$\frac{28}{15}\approx 1.866666667$

Multiply $2$ and $3$ to get $6$.

$$\frac{6+2}{3}\times \frac{7}{10}$$

Add $6$ and $2$ to get $8$.

$$\frac{8}{3}\times \frac{7}{10}$$

Multiply $\frac{8}{3}$ times $\frac{7}{10}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 7}{3\times 10}$$

Do the multiplications in the fraction $\frac{8\times 7}{3\times 10}$.

$$\frac{56}{30}$$

Reduce the fraction $\frac{56}{30}$ to lowest terms by extracting and canceling out $2$.

$$\frac{28}{15}$$

$\frac{2 ^ {2} \cdot 7}{3 \cdot 5} = 1\frac{13}{15} = 1.8666666666666667$