Solve 2(2)/(5)\div1(1)/(4) | Equatix

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Question

$$2 \frac{ 2 }{ 5 } \div 1 \frac{ 1 }{ 4 }$$

$\frac{48}{25}=1.92$

Divide $\frac{2\times 5+2}{5}$ by $\frac{1\times 4+1}{4}$ by multiplying $\frac{2\times 5+2}{5}$ by the reciprocal of $\frac{1\times 4+1}{4}$.

$$\frac{\left(2\times 5+2\right)\times 4}{5\left(1\times 4+1\right)}$$

Multiply $2$ and $5$ to get $10$.

$$\frac{\left(10+2\right)\times 4}{5\left(1\times 4+1\right)}$$

Add $10$ and $2$ to get $12$.

$$\frac{12\times 4}{5\left(1\times 4+1\right)}$$

Multiply $12$ and $4$ to get $48$.

$$\frac{48}{5\left(1\times 4+1\right)}$$

Multiply $1$ and $4$ to get $4$.

$$\frac{48}{5\left(4+1\right)}$$

Add $4$ and $1$ to get $5$.

$$\frac{48}{5\times 5}$$

Multiply $5$ and $5$ to get $25$.

$$\frac{48}{25}$$

$\frac{2 ^ {4} \cdot 3}{5 ^ {2}} = 1\frac{23}{25} = 1.92$