Question

$$2\frac{3}{5}+4\frac{3}{7}$$

Evaluate

$\frac{246}{35}\approx 7.028571429$

Show Solution

Factor

$\frac{2 \cdot 3 \cdot 41}{5 \cdot 7} = 7\frac{1}{35} = 7.0285714285714285$