How to solve 2 3/8 + 9/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 3/8 + 9/15 | Equatix

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$$2\frac{3}{8}+\frac{9}{15}$$

$\frac{119}{40}=2.975$

Multiply $2$ and $8$ to get $16$.

$$\frac{16+3}{8}+\frac{9}{15}$$

Add $16$ and $3$ to get $19$.

$$\frac{19}{8}+\frac{9}{15}$$

Reduce the fraction $\frac{9}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{19}{8}+\frac{3}{5}$$

Least common multiple of $8$ and $5$ is $40$. Convert $\frac{19}{8}$ and $\frac{3}{5}$ to fractions with denominator $40$.

$$\frac{95}{40}+\frac{24}{40}$$

Since $\frac{95}{40}$ and $\frac{24}{40}$ have the same denominator, add them by adding their numerators.

$$\frac{95+24}{40}$$

Add $95$ and $24$ to get $119$.

$$\frac{119}{40}$$

$\frac{7 \cdot 17}{2 ^ {3} \cdot 5} = 2\frac{39}{40} = 2.975$